Beautiful Days at the Movies - HackerRank || HackerRank Beautiful Days at the Movies Solution

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a, b, c, count = 0;
    scanf("%d %d %d", &a, &b, &c);
    for (int i = a; i <= b; i++)
    {
        int p = i, rev = 0;
        while (p != 0)
        {
            rev = rev * 10 + (p % 10);
            p = p / 10;
        }
        if (abs(rev - i) % c == 0) count++;
    }
    printf("%d\n",count);
    return 0;
}

#include <bits/stdc++.h>

using namespace std;

int main()
{
    int m, n, k, count = 0;
    cin >> m >> n >> k;

    for (int i = m; i <= n; i++)
    {
        int number = i, reversed = 0;

        while (number != 0)
        {
            reversed = (reversed * 10) + (number % 10);
            number /= 10;
        }

        if (abs(i - reversed) % k == 0)
        {
            count++;
        }
    }
    cout << count << endl;

    return 0;
}

import java.util.Scanner;

public class Beautiful_Days_at_the_Movies {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        int m = input.nextInt();
        int n = input.nextInt();
        int k = input.nextInt();
        int count = 0;
        for (int i = m; i <= n; i++) {
            int number = i, reversed = 0;
            while (number != 0) {
                reversed = (reversed * 10) + (number % 10);
                number /= 10;
            }
            if ((Math.abs(i - reversed)) % k == 0) count++;
        }
        System.out.println(count);
    }
}